Remaining changes
Wolfgang Corcoran-Mathe
(04 Sep 2020 17:12 UTC)
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Re: Remaining changes
John Cowan
(05 Sep 2020 03:41 UTC)
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(missing)
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(missing)
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(missing)
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Fwd: Remaining changes
Marc Nieper-Wißkirchen
(06 Sep 2020 07:43 UTC)
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Re: Remaining changes
Marc Nieper-Wißkirchen
(06 Sep 2020 09:33 UTC)
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Re: Remaining changes
Wolfgang Corcoran-Mathe
(06 Sep 2020 17:24 UTC)
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Re: Remaining changes
Marc Nieper-Wißkirchen
(06 Sep 2020 17:30 UTC)
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Re: Remaining changes
Wolfgang Corcoran-Mathe
(06 Sep 2020 17:40 UTC)
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Re: Remaining changes
John Cowan
(06 Sep 2020 20:04 UTC)
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Re: Remaining changes
Marc Nieper-Wißkirchen
(06 Sep 2020 20:40 UTC)
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Re: Remaining changes
John Cowan
(07 Sep 2020 00:03 UTC)
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Re: Remaining changes
Marc Nieper-Wißkirchen
(07 Sep 2020 06:31 UTC)
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Re: Remaining changes
Wolfgang Corcoran-Mathe
(07 Sep 2020 15:46 UTC)
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Re: Remaining changes Wolfgang Corcoran-Mathe (07 Sep 2020 20:56 UTC)
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Re: Remaining changes
John Cowan
(07 Sep 2020 21:16 UTC)
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Re: Remaining changes
Wolfgang Corcoran-Mathe
(07 Sep 2020 21:57 UTC)
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Re: Remaining changes
Marc Nieper-Wißkirchen
(08 Sep 2020 14:25 UTC)
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Re: Remaining changes
John Cowan
(08 Sep 2020 15:26 UTC)
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Fwd: Remaining changes
John Cowan
(05 Sep 2020 17:48 UTC)
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Fwd: Remaining changes
Marc Nieper-Wißkirchen
(05 Sep 2020 12:59 UTC)
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Re: Remaining changes
Marc Nieper-Wißkirchen
(05 Sep 2020 13:07 UTC)
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On 2020-09-07 11:44 -0400, Wolfgang Corcoran-Mathe wrote: > On 2020-09-07 08:31 +0200, Marc Nieper-Wißkirchen wrote: > > >> So, actually, procedures like range-every (that have to > > >> inspect all ranges at least once) also need addition of O(k). > > > > > > > > > But that's done in the proc argument, and running time there is not > > > counted. I've made the change, but it's easy to roll back if I'm correct. > > > > All the zillion ranges passed to range-every can be empty so proc is > > never called. But range-length will have to be called on them. That's > > why it needs at least O(k) time. > > Indeed. A zillion empty ranges is a fast case for range-every, but > we must still determine that they are all empty. (Again, a slight oversimplification. We need only determine that one of the zillion ranges is empty to short-circuit. In the worst case, we still need to check all k ranges.) -- Wolfgang Corcoran-Mathe <xxxxxx@sigwinch.xyz>