Twos complement assumption, other issues | Laura Dickey | 15 Jan 2005 17:44 UTC |

Re: Twos complement assumption, other issues | Aubrey Jaffer | 27 Jan 2005 19:00 UTC |

Re: Twos complement assumption, other issues | Bradd W. Szonye | 27 Jan 2005 19:04 UTC |

Re: Twos complement assumption, other issues | Aubrey Jaffer | 29 Jan 2005 00:53 UTC |

Re: Twos complement assumption, other issues

*Bradd W. Szonye*27 Jan 2005 19:04 UTCAubrey Jaffer wrote: > Since we treat integers as having two's-complement negations, the > two's-complement of an integer is its negation. The one's-complement > of an integer is computed by lognot: > > (define (lognot n) (- -1 n)) Isn't that backwards? Complement and negation are equivalent in ones- complement arithmetic; in twos-complement, the complement is equal to negation minus one. Perhaps I'm not understanding your explanation clearly. -- Bradd W. Szonye http://www.szonye.com/bradd