| Date: Thu, 27 Jan 2005 11:04:24 -0800
 | From: "Bradd W. Szonye" <xxxxxx@szonye.com>
 |
 | Aubrey Jaffer wrote:
 | >  Since we treat integers as having two's-complement negations,
 | >  the two's-complement of an integer is its negation.  The
 | >  one's-complement of an integer is computed by lognot:
 | >
 | >  (define (lognot n) (- -1 n))
 |
 | Isn't that backwards? Complement and negation are equivalent in
 | ones- complement arithmetic; in twos-complement, the complement is
 | equal to negation minus one.  Perhaps I'm not understanding your
 | explanation clearly.

Taking the one's-complement of a number is the process of exchanging
'1' for '0' and '0' for '1'.  That is LOGNOT.

When we talk of *'s-complement representation, it is about which
process is used to negate a number.

SRFI-60 treats its integers as two's-complement.  Therefore the
process of taking the one's-complement is different from the native
negation.

It is difficult to keep straight.  In the specification section, the
description of LOGNOT incorrectly says two's-complement.