Last call
Takashi Kato
(30 Jun 2013 07:00 UTC)
|
Re: Last call
Per Bothner
(30 Jun 2013 07:46 UTC)
|
Re: Last call
Takashi Kato
(30 Jun 2013 08:35 UTC)
|
Re: Last call
Per Bothner
(30 Jun 2013 15:47 UTC)
|
Re: Last call Takashi Kato (30 Jun 2013 17:01 UTC)
|
Re: Last call
Per Bothner
(30 Jun 2013 17:19 UTC)
|
Re: Last call
Takashi Kato
(30 Jun 2013 17:47 UTC)
|
Re: Last call
Per Bothner
(30 Jun 2013 18:04 UTC)
|
Re: Last call
Takashi Kato
(30 Jun 2013 18:29 UTC)
|
Re: Last call
Per Bothner
(30 Jun 2013 23:11 UTC)
|
Re: Last call
John Cowan
(01 Jul 2013 20:01 UTC)
|
Re: Last call
Shiro Kawai
(30 Jun 2013 09:02 UTC)
|
Re: Last call
Takashi Kato
(30 Jun 2013 09:30 UTC)
|
Re: Last call
Shiro Kawai
(30 Jun 2013 09:54 UTC)
|
Re: Last call
Takashi Kato
(30 Jun 2013 10:27 UTC)
|
Re: Last call
Shiro Kawai
(30 Jun 2013 11:44 UTC)
|
Re: Last call
Takashi Kato
(30 Jun 2013 17:02 UTC)
|
On 30/06/2013 17:47, Per Bothner wrote: > For an input/output port there are two positions - because there are > actually two separate ports. I disagree with this. It seems the point is mixed up with Java's problem and how port should be. IMO input/output port doesn't have to (or even must not) have two positions and it is one port. (At least I implemented it like this in Sagittarius.) > One could so that, but that means causes compatibility problems with > the Java I/O classes. InputStream/OutputStream/Reader/Writer are > all classes, not interfaces, so you can't multiply inherit them. IMO this is a big mistake of Java. (well this is not the topic what I want to discuss but just wanted to say.) > Obviously it is possible to implement InputOutputPort in Java, > as you show. (I had to make some contortions to deal with binary > ports.)However, the concept is inherently bogus, so it would be > a mistake to do so. If Java's stream and Scheme's port are the same yes, but if it's different I don't think so, and I think (at least with this case) it should be different because of the Java's limitation. And I believe converting port to stream (or reader/writer) is not so difficult. > If you want an object that bundles both an input port and an > output port, then use the socket directly. That is what > C# does - it doesn't even let you (directly) get the two > streams, but you call Send/Receive directly on the Socket. For this, removing 'socket-port' is an option. As long as implementations support custom port, then converting socket to port is not so difficult. The purpose of this procedure is actually convenience and reducing implementation dependent layer. _/_/ Takashi Kato E-mail: xxxxxx@ymail.com