Re: various comments
Jussi Piitulainen
(17 Nov 2001 14:03 UTC)
|
Re: various comments
Radey Shouman
(17 Nov 2001 18:27 UTC)
|
Re: various comments
Jussi Piitulainen
(18 Nov 2001 14:50 UTC)
|
Re: various comments Per Bothner (19 Nov 2001 19:52 UTC)
|
Re: various comments
Jussi Piitulainen
(20 Nov 2001 08:14 UTC)
|
Re: various comments
Per Bothner
(20 Nov 2001 18:35 UTC)
|
Re: various comments
Jussi Piitulainen
(20 Nov 2001 19:20 UTC)
|
Re: various comments
Per Bothner
(20 Nov 2001 19:33 UTC)
|
Re: various comments
Jussi Piitulainen
(20 Nov 2001 20:14 UTC)
|
Re: various comments
Radey Shouman
(21 Nov 2001 03:31 UTC)
|
Re: various comments
Radey Shouman
(19 Nov 2001 23:26 UTC)
|
Re: various comments
Jussi Piitulainen
(20 Nov 2001 08:43 UTC)
|
Re: various comments
Per Bothner
(20 Nov 2001 19:20 UTC)
|
Re: various comments
Jussi Piitulainen
(20 Nov 2001 20:02 UTC)
|
Re: various comments
Per Bothner
(20 Nov 2001 21:08 UTC)
|
Re: various comments
Radey Shouman
(21 Nov 2001 03:58 UTC)
|
Re: various comments
Jussi Piitulainen
(21 Nov 2001 16:52 UTC)
|
Re: various comments
Radey Shouman
(21 Nov 2001 03:47 UTC)
|
Vectors as arrays Re: various comments
Jussi Piitulainen
(20 Nov 2001 18:03 UTC)
|
Re: Vectors as arrays Re: various comments
Radey Shouman
(21 Nov 2001 04:09 UTC)
|
Jussi Piitulainen wrote: >If both (vector? arr) and (array? arr) yield #t, then (vector-ref arr >k) must do what (array-ref arr k) does, and so on. To implement that, >one should first have disjoint types, (r5rs-vector? o) and (array? o), >and then make (vector? o) be their sum (or (r5rs-vector? o) (array? >o)), and (vector-ref o k) would dispatch to one of (r5rs-vector-ref o >k) or (array-ref o k). > Not sure what you mean, but it sounds wrong. Instead we should follow logic and Common Lisp (or at least let implementations have that option): (vector? obj) should imply (array? obj). The reverse would be true if you take the view that arrays are nested vectors, but that runs into problems in de-generative cases of a 0-rank array. It also is difficult to distinguish a 0*M array from a 0*N array since you can't really distinguish a 0-length vector each of whose non-existent elements is an M-length vectors from a 0-length vector of N-length vectors. That is unless you can associate "types" with empty vectors. Some APL dialects to that, and it gets a little strange. --Per Bothner